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Published July 2, 2026

Vectors and Translations

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Translations and Vectors

A translation is a key mathematical transformation that slides a shape from one place to another without turning or resizing it. We use special instructions called vectors to describe this movement precisely — a skill used everywhere from video game design to sports coaching.

Understanding Translations and Column Vectors

What is a Translation?

A translation is a “slide”. Every point on the shape moves the exact same distance in the exact same direction. The shape’s size and orientation do not change.

A blue triangle labelled Object slides to the right and up, becoming a red triangle labelled Image. A dashed arrow shows the direction and distance of the translation. Two triangles connected by a dashed arrow. The left triangle (Object) is blue. The right triangle (Image) is red and positioned higher up and to the right. The arrow indicates the direction of the translation. Object Image

Using a Column Vector

We use a column vector to give the precise instructions for the slide.

$\begin{pmatrix} x \\ y \end{pmatrix}$ where $x$ = horizontal (+right / −left) and $y$ = vertical (+up / −down)

Example: The vector $\begin{pmatrix} 4 \\ -2 \end{pmatrix}$ means move 4 units right and 2 units down.

Worked Examples

Example 1: Translating a Shape

Translate triangle PQR by the vector $\begin{pmatrix} -4 \\ -3 \end{pmatrix}$.

Move every point 4 left and 3 down.

Triangle PQR (blue) at coordinates P(2,4), Q(5,4), R(3,6) translated 4 left and 3 down to P-prime Q-prime R-prime (red) at P-prime(-2,1), Q-prime(1,1), R-prime(-1,3). The translation is verified correct. Two triangles on a coordinate grid. The blue triangle is PQR in the upper right area. The red triangle P-prime Q-prime R-prime is in the lower left area, showing the result of translating by (-4, -3). PQR P’Q’R’

Example 2: Finding the Vector

Describe the translation from shape A to shape B using a column vector.

Two triangles on a coordinate grid. Triangle A (blue) has its bottom-left corner at (1,1). Triangle B (red) has its bottom-left corner at (4,3). An arrow from (1,1) to (4,3) shows the translation of 3 right and 2 up. A blue triangle labelled A and a red triangle labelled B on a grid. A dashed arrow connects corresponding vertices, indicating the direction and magnitude of the translation. A B
  1. Pick a corresponding point on both shapes, e.g., the bottom-left corner.
  2. Horizontal change ($x$): From $x=1$ to $x=4$ → $+3$.
  3. Vertical change ($y$): From $y=1$ to $y=3$ → $+2$.

Answer: $\begin{pmatrix} 3 \\ 2 \end{pmatrix}$

Tutor Insights

🤔 Common Misunderstandings

  • Mixing up $x$ and $y$. Putting the vertical movement on top and horizontal on the bottom. Remember: $x$ is across, $y$ is up/down.
  • Incorrect signs. Forgetting that moving left means a negative $x$-value and moving down means a negative $y$-value.

📝 Common Exam Mistakes

  • Flipping the vector components in the final answer.
  • Miscounting squares on the grid when drawing or describing a translation.
  • Not translating all vertices, leading to an incorrectly drawn image.

Practice Questions

  1. Point P is at $(3, 2)$. It is translated by $\begin{pmatrix} 2 \\ 4 \end{pmatrix}$. What are the coordinates of its image, P’?
  2. Triangle ABC has vertices $A(1,1)$, $B(4,1)$, $C(2,3)$. It is translated by $\begin{pmatrix} -3 \\ 2 \end{pmatrix}$. What are the coordinates of A’B’C’?
  3. An object is at $(5, 6)$ and its image after a translation is at $(1, 3)$. Write down the column vector for this translation.
  4. A shape is translated by $\begin{pmatrix} 2 \\ -5 \end{pmatrix}$. If one point on the image is at $(0, 0)$, what were the coordinates of the corresponding point on the original object?
Show Answers
  1. Working: New $x = 3+2 = 5$. New $y = 2+4 = 6$.
    Answer: $(5, 6)$.
  2. Working: $A(1,1) \to (-2,3)$. $B(4,1) \to (1,3)$. $C(2,3) \to (-1,5)$.
    Answer: A'(−2, 3), B'(1, 3), C'(−1, 5).
  3. Working: $x$-movement $= 1-5 = -4$. $y$-movement $= 3-6 = -3$.
    Answer: $\begin{pmatrix} -4 \\ -3 \end{pmatrix}$.
  4. Working: Apply the reverse vector $\begin{pmatrix} -2 \\ 5 \end{pmatrix}$ to $(0,0)$.
    Answer: $(−2, 5)$.

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