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Published June 13, 2026

Rearranging Formulae (Changing the Subject)

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Rearranging Formulae

Rearranging formulae is a vital algebra skill that allows you to change the “subject” of a formula to find any unknown value. It’s like having a recipe for 4 people and adapting it to cook for 8 – you’re changing the formula to suit your needs!

The Core Method: Balance and Inverses

Think of a formula as a balanced scale. Whatever you do to one side, you must do to the other. To isolate a variable and make it the new subject, we “undo” the operations around it using inverse (opposite) operations.

Key Inverse Operations

  • Addition (+) ↔ Subtraction (−)
  • Multiplication (×) ↔ Division (÷)
  • Squaring ($x^2$) ↔ Square Root ($\sqrt{x}$)
  • Cubing ($x^3$) ↔ Cube Root ($\sqrt[3]{x}$)
A balanced scale representing the formula x + 3 = y. The left pan is labelled x + 3 and the right pan is labelled y. Both pans are level, showing the two sides are equal. A balance scale with a central pivot, a horizontal beam, and two hanging pans at equal heights. The left pan shows x + 3 and the right pan shows y. x + 3 y

Worked Examples

Example 1: One-Step (Add/Subtract)

Make $V$ the subject of $P = V + C$.

To undo adding $C$, subtract $C$ from both sides.

$P – C = V + C – C$
$P – C = V$
$V = P – C$

Example 2: One-Step (Multiply/Divide)

Make $S$ the subject of $D = ST$.

To undo multiplying by $T$, divide both sides by $T$.

$\frac{D}{T} = \frac{ST}{T}$
$S = \frac{D}{T}$

Example 3: Two-Step Rearrangement

Make $x$ the subject of $y = 4x – 7$.

Undo operations in reverse BIDMAS order.

  1. Undo the subtraction — add 7 to both sides: $y + 7 = 4x$.
  2. Undo the multiplication — divide by 4: $\frac{y + 7}{4} = x$.

Answer: $x = \frac{y + 7}{4}$

Example 4: Subject on Both Sides

Make $x$ the subject of $ax + b = cx$.

  1. Collect $x$ terms on one side: $ax – cx + b = 0$.
  2. Move other terms to the other side: $ax – cx = -b$.
  3. Factorise out the subject: $x(a – c) = -b$.
  4. Divide to isolate $x$: $x = \frac{-b}{a – c}$.

Answer: $x = \frac{-b}{a – c}$ (equivalently, $x = \frac{b}{c – a}$)

Tutor Insights

🤔 Common Misunderstandings

  • Order of operations: Forgetting to “undo” in the reverse order of BIDMAS — deal with addition/subtraction before multiplication/division.
  • Signs: Forgetting to change the sign when moving a term across the equals sign.
  • Division errors: When dividing a whole side, forgetting to divide every term. For $2x = y + z$, the answer is $x = \frac{y + z}{2}$, not $x = \frac{y}{2} + z$.

📝 Common Exam Mistakes

  • Incorrect inverse operations: Squaring instead of square rooting, or adding instead of subtracting.
  • Not factorising when necessary: Forgetting to factorise out the subject when it appears in multiple terms — a common higher-tier mistake.
  • Messy working: Disorganised steps can easily lead to errors. Show one step per line.

Practice Questions

Try these questions to test your skills!

  1. Make $k$ the subject of: $m = k – 5$.
  2. Make $a$ the subject of: $P = 3a + b$.
  3. Make $r$ the subject of: $C = 2\pi r$.
  4. Make $h$ the subject of: $V = \frac{1}{3}\pi r^2 h$.
  5. Make $k$ the subject of: $7k – 2m = 3k + 5m$.
Show Answers
  1. Working: Add 5 to both sides.
    Answer: $k = m + 5$
  2. Working: Subtract $b$, then divide by 3.
    Answer: $a = \frac{P – b}{3}$
  3. Working: Divide both sides by $2\pi$.
    Answer: $r = \frac{C}{2\pi}$
  4. Working: Multiply both sides by 3, then divide by $\pi r^2$.
    Answer: $h = \frac{3V}{\pi r^2}$
  5. Working: $7k – 3k = 5m + 2m \implies 4k = 7m$.
    Answer: $k = \frac{7m}{4}$

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