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Published June 26, 2026

Pythagoras’ Theorem

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Pythagoras’ Theorem

Pythagoras’ Theorem is a powerful tool for finding missing lengths in right-angled triangles. It’s a fundamental part of geometry used in architecture, engineering, navigation, and computer graphics.

The Core Concept

For any right-angled triangle, the square of the longest side (the hypotenuse) equals the sum of the squares of the other two sides.

A right-angled triangle with sides labelled a (base), b (vertical side), and c (hypotenuse). The right angle is marked at the bottom-left corner. A green right-angled triangle. The horizontal base is labelled a, the vertical left side is labelled b, and the hypotenuse (the longest side, slanting from top-left to bottom-right) is labelled c. A small red square marks the right angle at the bottom-left corner. a b c (hypotenuse)
$a^2 + b^2 = c^2$

How to Use the Theorem

Finding the Hypotenuse

If you know the two shorter sides ($a$ and $b$), find the hypotenuse ($c$).

  1. Square both shorter sides ($a^2$ and $b^2$).
  2. Add them together: $a^2 + b^2$.
  3. Square root the result to find $c$.

Finding a Shorter Side

If you know the hypotenuse ($c$) and one shorter side ($a$), find the other ($b$).

  1. Square both known sides: $c^2$ and $a^2$.
  2. Subtract: $c^2 – a^2$.
  3. Square root the result to find $b$.

Worked Examples

Example 1: Finding the Hypotenuse

A ladder leans against a wall. The wall is 4 m high and the base of the ladder is 3 m from the wall. How long is the ladder?

A right-angled triangle representing a ladder against a wall. The vertical side is 4 m (the wall), the horizontal base is 3 m (the ground distance), and the hypotenuse (the ladder) is labelled c with a question mark. A green right-angled triangle with the right angle at the bottom-left. The base is labelled 3 m, the vertical side is labelled 4 m, and the slanted hypotenuse is labelled c?. 3 m 4 m c ?
  1. Square the shorter sides: $3^2 = 9$ and $4^2 = 16$.
  2. Add them: $9 + 16 = 25$.
  3. Square root: $\sqrt{25} = 5$.

Answer: The ladder is 5 m long.

Example 2: Finding a Shorter Side

A TV has a diagonal of 50 inches and a height of 30 inches. What is its width?

A rectangle representing a TV screen with width b (unknown) and height 30 inches. The diagonal line across the screen is 50 inches. A green rectangle with a diagonal line from the top-left corner to the bottom-right corner. The diagonal is labelled 50 in (the hypotenuse), the left side is labelled 30 in (height), and the bottom edge is labelled b? (the unknown width). 50 in 30 in b ?
  1. The diagonal is the hypotenuse. Square both known values: $50^2 = 2500$ and $30^2 = 900$.
  2. Subtract: $2500 – 900 = 1600$.
  3. Square root: $\sqrt{1600} = 40$.

Answer: The width is 40 inches.

Tutor Insights

🤔 Common Misunderstandings

  • Mixing up which side is the hypotenuse (c). It’s always the longest side, opposite the right angle.
  • Forgetting to square root at the end. Students often find $c^2$ and stop there.
  • Adding instead of subtracting when finding a shorter side.

📝 Common Exam Mistakes

  • Incorrectly identifying the hypotenuse in a word problem.
  • Calculation errors when squaring or square rooting.
  • Applying the theorem to non-right-angled triangles — it only works with a 90° angle.
  • Forgetting units in the final answer.

Practice Questions

  1. A right-angled triangle has shorter sides of 6 cm and 8 cm. Calculate the length of the hypotenuse.
  2. A right-angled triangle has a hypotenuse of 13 cm and one shorter side of 5 cm. Calculate the length of the other shorter side.
  3. A rectangular field is 80 m long and 60 m wide. What is the length of the diagonal path across the field?
Show Answers
  1. Working: $6^2 + 8^2 = 36 + 64 = 100$. $c = \sqrt{100} = 10$.
    Answer: 10 cm.
  2. Working: $13^2 – 5^2 = 169 – 25 = 144$. $b = \sqrt{144} = 12$.
    Answer: 12 cm.
  3. Working: $80^2 + 60^2 = 6400 + 3600 = 10000$. $c = \sqrt{10000} = 100$.
    Answer: 100 m.

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