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Published July 17, 2026

Instantaneous Rates of Change

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Instantaneous Rates of Change

The speed shown on your car’s speedometer at a specific moment is an instantaneous rate of change. This guide explores how to estimate this from a curved graph by finding the gradient of a tangent — a key higher-tier skill.

Average vs. Instantaneous Rate of Change

Average Rate of Change

Calculated over an interval. On a graph it’s the gradient of the chord — a straight line connecting two points on the curve.

A curved graph. A blue dashed chord connects two points on the curve, illustrating the average rate of change over that interval. A green curve rises then falls. A blue dashed straight line connects two points on the curve, representing the chord whose gradient gives the average rate of change. Chord

Instantaneous Rate of Change

The rate at a specific moment. On a graph it’s the gradient of the tangent — a straight line that just touches the curve at exactly one point.

A curved graph. A red dashed tangent line just touches the curve at a single point, illustrating the instantaneous rate of change at that moment. A green curve rises then falls. A red dashed straight line skims the curve at exactly one point, representing the tangent whose gradient gives the instantaneous rate of change. Tangent

How to Estimate the Gradient of a Curve

  1. Locate the point on the curve where you need the rate of change.
  2. Draw a tangent at that point using a ruler. It should “kiss” the curve and match its steepness there.
  3. Choose two clear points on your tangent line that are easy to read from the grid.
  4. Calculate the gradient: $\dfrac{\text{change in }y}{\text{change in }x}$.
  5. Interpret your answer in context, including the correct units.

Worked Example

Estimating Speed from a Distance-Time Graph

Estimate the speed of the car at $t = 6$ seconds.

A distance-time graph showing a curve rising from the origin. At t equals 6 seconds, the point on the curve is marked and a tangent line is drawn. The tangent passes through (4,20) and (8,36), giving a gradient of 4 metres per second. A curved distance-time graph with a blue S-shaped curve. At t equals 6, a red dot marks the point on the curve. A dark green dashed tangent line is drawn through that point, with a right-angle gradient triangle showing rise of 16 metres over run of 4 seconds. Time (s) Distance (m) 0 2 4 6 8 10 0 10 20 30 40 4 s 16 m t=6
  1. Draw a tangent to the curve at the point where $t = 6$.
  2. Read two clear points on the tangent: $(4, 20)$ and $(8, 36)$.
  3. Calculate the gradient: $\dfrac{36 – 20}{8 – 4} = \dfrac{16}{4} = 4$.
  4. Interpret: The gradient of a distance-time graph is speed.

Answer: The speed at $t = 6$ s is approximately $4 \text{ m/s}$.

Tutor Insights

🤔 Common Misunderstandings

  • Drawing a chord instead of a tangent. A chord connects two points; a tangent just touches the curve at one.
  • Reading points off the curve to calculate the gradient, rather than off the tangent line you’ve drawn.

📝 Common Exam Mistakes

  • Inaccurate tangent drawing. A poorly drawn tangent will give an answer outside the accepted range.
  • Not showing the tangent line on the graph — the examiner needs to see it.
  • Forgetting units (e.g., m/s for speed, m/s² for acceleration) in the final answer.

Practice Questions

  1. Explain the difference between a chord and a tangent on a curve.
  2. The gradient of a velocity-time graph represents a specific quantity. What is it?
  3. On the distance-time graph in the worked example, is the car speeding up or slowing down at $t = 6$ seconds? How can you tell?
Show Answers
  1. A chord connects two different points on a curve. A tangent touches the curve at a single point without crossing it.
  2. The gradient of a velocity-time graph represents acceleration.
  3. The car is slowing down. The curve is becoming less steep over time, meaning the gradient (speed) is decreasing.

Need Help with Rates of Change?

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