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Published September 10, 2025

Expanding Three or More Brackets

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Alice Cook
Alice is a specialist tutor with over 10 years of experience supporting neurodiverse students and those with SEN. As a BDA Accredited Tutor and qualified dyslexia teacher, she excels at creating safe, non-pressured learning environments. Alice specialises in relieving maths anxiety and uses a creative, student-centred approach to help learners of all ages gain qualifications and confidence.
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Expanding Three Brackets

Expanding three or more brackets is a key higher-tier algebra skill. It’s used to find the volume of 3D shapes, solve complex equations, and is a fundamental building block for more advanced maths. This guide will show you the clear, step-by-step process to master it.

The Core Method: A Sequential Process

You can’t multiply three brackets all at once. The key is to do it in a sequence: expand the first two brackets, simplify the result, and then multiply that new expression by the third bracket.

(A)(B)(C) Step 1 (Result of A×B)(C) Step 2 Final Answer

Recap: Expanding Two Brackets

The first step always involves expanding two brackets. You can use the FOIL method or the Grid method.

The FOIL Method

For $(x+2)(x+5)$:

  • First: $x \times x = x^2$
  • Outer: $x \times 5 = 5x$
  • Inner: $2 \times x = 2x$
  • Last: $2 \times 5 = 10$

Combine: $x^2 + 5x + 2x + 10 = \mathbf{x^2 + 7x + 10}$.

The Grid Method

For $(x+2)(x+5)$:

× $x$ $+2$
$x$ $x^2$ $2x$
$+5$ $5x$ $10$

Combine terms: $x^2 + 2x + 5x + 10 = \mathbf{x^2 + 7x + 10}$.

Worked Example

Expand and simplify $(x+1)(x-2)(x+3)$

  1. Step 1: Expand the first two brackets.
    $(x+1)(x-2) = x^2 – 2x + x – 2 = x^2 – x – 2$.

    Now the problem is: $(x^2 – x – 2)(x+3)$
  2. Step 2: Multiply the result by the third bracket.
    Multiply every term in the first bracket by every term in the second:
    $x^2(x+3) = x^3 + 3x^2$
    $-x(x+3) = -x^2 – 3x$
    $-2(x+3) = -2x – 6$
  3. Step 3: Combine and simplify all the terms.
    $x^3 + 3x^2 – x^2 – 3x – 2x – 6$
    $= x^3 + (3x^2 – x^2) + (-3x – 2x) – 6$

Answer: $x^3 + 2x^2 – 5x – 6$

Tutor Insights

🤔 Common Misunderstandings

  • Trying to multiply all three brackets at once. It must be done sequentially: expand two, then multiply by the third.
  • Not fully understanding “like terms”. You can only combine terms with the exact same variable and power (e.g., $x^2$ and $x^2$, but not $x^2$ and $x$).

📝 Common Exam Mistakes

  • Sign errors. This is the most frequent mistake! Forgetting that a negative times a negative is a positive, or dropping a negative sign in your workings.
  • Missing terms. Forgetting to multiply every term from the first result by every term in the next bracket.
  • Incorrect simplification after expanding.

Practice Questions

  1. Expand and simplify: $(x+1)(x+2)(x+3)$
  2. Expand and simplify: $(x-1)(x+2)(x-3)$
  3. Expand and simplify: $(x+3)^3$
Show Answers
  1. Working: $(x^2 + 3x + 2)(x+3) = x^3 + 3x^2 + 3x^2 + 9x + 2x + 6$.
    Answer: $x^3 + 6x^2 + 11x + 6$.
  2. Working: $(x^2 + x – 2)(x-3) = x^3 – 3x^2 + x^2 – 3x – 2x + 6$.
    Answer: $x^3 – 2x^2 – 5x + 6$.
  3. Working: $(x+3)(x+3)(x+3) = (x^2 + 6x + 9)(x+3) = x^3 + 3x^2 + 6x^2 + 18x + 9x + 27$.
    Answer: $x^3 + 9x^2 + 27x + 27$.

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